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Q.1. Write electrode reactions net cell reaction in the electrolysis of molten barium chloride.

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✓ Free question

Step 1. Molten BaCl2 contains freely mobile Ba2+ and Cl- ions, exactly analogous to molten NaCl but with a divalent cation.

Step 2. At the cathode, Ba2+ is reduced: Ba2+(l)+2e−→Ba(l)Ba^{2+}(l)+2e^-\rightarrow Ba(l).

Step 3. At the anode, Cl- is oxidised: 2Cl−(l)→Cl2(g)+2e−2Cl^-(l)\rightarrow Cl_2(g)+2e^-.

Step 4. Both half reactions already involve 2 electrons, so they add directly: Ba2+(l)+2Cl−(l)→Ba(l)+Cl2(g)Ba^{2+}(l)+2Cl^-(l)\rightarrow Ba(l)+Cl_2(g).

✓Final answer

Cathode: Ba2+(l)+2e- -> Ba(l). Anode: 2Cl-(l) -> Cl2(g)+2e-. Net: Ba2+(l)+2Cl-(l) -> Ba(l)+Cl2(g).

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