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Activity · Q2

Q.2. Prepare the salt bridge and set up the Daniel cell in your laboratory. Measure its emf using voltmeter and compare it with the value calculated from the information in Table 5.1

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Step 1. Prepare two half cells: a zinc strip in 1M ZnSO4 solution, and a copper strip in 1M CuSO4 solution, each in its own container.

Step 2. Connect the two solutions using a salt bridge (a U-tube of saturated KCl set in agar gel, section 5.6.1), and connect the two metal strips externally through a voltmeter.

Step 3. From Table 5.1, E0(Cu2+/Cu)=+0.337V (often rounded 0.34V) and E0(Zn2+/Zn)=-0.763V (often rounded -0.76V); since Cu has the higher E0, it is the cathode and Zn the anode.

Step 4. Calculated Ecell0=ECu0−EZn0=0.337−(−0.763)=1.10 VE^0_{cell}=E^0_{Cu}-E^0_{Zn}=0.337-(-0.763)=1.10\,V.

Step 5. The voltmeter's actual measured reading is generally slightly LOWER than this calculated 1.10V, because real solutions are never exactly 1M, and factors like internal cell resistance and the liquid-junction potential at the salt bridge introduce small departures from the ideal standard-state prediction.

✓Final answer

Prepare a salt bridge (section 5.6.1) between a Zn/ZnSO4 half cell and a Cu/CuSO4 half cell to form Zn(s)|Zn2+(1M)||Cu2+(1M)|Cu(s). Calculated E0cell = E0Cu - E0Zn = 0.337V - (-0.763V) = 1.10 V; the voltmeter reading in the actual lab setup is typically slightly LOWER than this, due to internal resistance, liquid-junction potential at the salt bridge, and any deviation from exactly 1M concentrations.

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