Q.Find out the values of ionic product $K_w$ of water at various temperatures. 273 K, 283K, 293K, 303K, 313K, 323 K

Step 1. This is a look-up task, so the values below are drawn from standard published physical-chemistry reference tables for the ionic product of water (not from this chapter's own text, which gives only the 298 K value of 1.0x10^-14) -- exact figures can differ slightly between sources, but the trend and the order of magnitude at each temperature are well established.

Step 2. 273 K (0 degC): Kw is approximately $0.11\times10^{-14}$.

Step 3. 283 K (10 degC): approximately $0.29\times10^{-14}$. 293 K (20 degC): approximately $0.68\times10^{-14}$.

Step 4. 298 K (25 degC): exactly $1.0\times10^{-14}$, matching Eq. (3.15) of this chapter.

Step 5. 303 K (30 degC): approximately $1.47\times10^{-14}$. 313 K (40 degC): approximately $2.92\times10^{-14}$. 323 K (50 degC): approximately $5.47\times10^{-14}$. …

Report standard published Kw-vs-temperature values (a genuine look-up task, not calculable from this chapter's own text alone) and conn …

• Treating Kw as fixed at 1.0x10^-14 regardless of temperature -- that value is specific to 298 K. …