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Choose the most correct option · Q7

Q.A living cell contains a solution which is isotonic with 0.3 M sugar solution. What osmotic pressure develops when the cell is placed in 0.1 M KCl solution at body temperature?
a. 5.08 atm
b. 2.54 atm
c. 4.92 atm
d. 2.46 atm

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Step 1. The cell's internal osmotic pressure equals that of 0.3 M sugar (nonelectrolyte, i=1): πcell=MRT=0.3×0.0821×310=7.635\pi_{cell}=MRT=0.3\times0.0821\times310=7.635 atm (body temperature = 37 degC = 310 K).

Step 2. The external 0.1 M KCl solution (electrolyte, i=2 for complete dissociation into K+ + Cl-) has osmotic pressure πKCl=iMRT=2×0.1×0.0821×310=5.090\pi_{KCl}=iMRT=2\times0.1\times0.0821\times310=5.090 atm. …

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