Skip to content
Question 85 of 97

Q.Define the following terms:

(i) Isotonic solution
(ii) Osmosis. Gold crystallises into face-centred cubic cells. The edge length of unit cell is 4.08×10−84.08 \times 10^{-8} cm. Calculate the density of gold. [Molar mass of gold = 197 g mol−1mol^{-1}]
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2022Subjective· 4mImportance★★★★★
88% · 85/97 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Isotonic solutions share the same osmotic pressure; osmosis is solvent flow through a membrane; gold's fcc unit cell gives a calculated density of about 19.27 g/cm³.

  1. Isotonic solution: Two solutions that exert the same osmotic pressure at a given temperature are said to be isotonic with each other. When separated by a semipermeable membrane, there is no net flow of solvent between two isotonic solutions.
  2. Osmosis: The spontaneous flow of solvent molecules from a region of lower solute concentration (or pure solvent) into a region of higher solute concentration, through a semipermeable membrane that allows only solvent molecules (not solute) to pass through. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.