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Question 96 of 97

Q.Calculate the osmotic pressure of solution containing 0.822 gm of sucrose in 300 mL of water at 298 K. [Given: Molar mass of sucrose 342 g/mol, R = 0.08205 dm3^3.atm.K−1^{-1}.mol−1^{-1}]

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 2mImportance★★★★★
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Using π=n2RTV\pi = \dfrac{n_2RT}{V} with n2=0.822/342n_2 = 0.822/342 mol gives π≈0.196\pi \approx 0.196 atm.

Moles of sucrose: n2=w2M2=0.822342=2.4035×10−3 moln_2 = \dfrac{w_2}{M_2} = \dfrac{0.822}{342} = 2.4035\times10^{-3}\ mol

Volume of solution: V=300 mL=0.300 LV = 300\ mL = 0.300\ L

Using the van't Hoff equation for osmotic pressure: π=n2RTV\pi = \dfrac{n_2RT}{V}

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