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Questions 4-15 · Q8

Q.Fish generally needs O₂ concentration in water at least 3.8 mg/L for survival. What partial pressure of O₂ above the water is needed for the survival of fish? Given the solubility of O₂ in water at 0⁰C and 1 atm partial pressure is 2.2 × 10⁻³ mol/L (0.054 atm)

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Step 1. Convert the required O2 concentration to mol/L: molar mass O2 = 32 g/mol, so 3.8 mg/L = 0.0038 g/L, giving 0.0038/32=1.1875×10−40.0038/32 = 1.1875\times10^{-4} mol/L.

Step 2. Find Henry's law constant from the given reference data: at 0 degC and 1 atm partial pressure, solubility = 2.2×10−32.2\times10^{-3} mol/L, so KH=S/P=2.2×10−3/1=2.2×10−3K_H = S/P = 2.2\times10^{-3}/1 = 2.2\times10^{-3} mol L-1 atm-1. …

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