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Question 83 of 97

Q.Henry's law constant for CH3Br(g)CH_3Br_{(g)} is 0.159 mol dm−3 bar−1dm^{-3}\,bar^{-1} at 25°C. What is solubility of CH3Br(g)CH_3Br_{(g)} in water at same temperature and partial pressure of 0.164 bar?

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2022Subjective· 1mImportance★★★★★
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Applying Henry's law directly gives the solubility of CH3BrCH_3Br gas in water.

By Henry's law, C=KH×pC = K_H \times p, where KH=0.159 mol dm−3bar−1K_H = 0.159\ mol\,dm^{-3}bar^{-1} and p=0.164 barp = 0.164\ bar: …

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