Skip to content
Exercise 6.3 · Q31

Q.Verify that y=a+bxy=a+\dfrac{b}{x} is a solution of xd2ydx2+2dydx=0x\dfrac{d^2y}{dx^2}+2\dfrac{dy}{dx}=0.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
18% · 31/177 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Differentiate y=a+bxy=a+\dfrac{b}{x} twice: dydx=−bx2\dfrac{dy}{dx}=-\dfrac{b}{x^2}, d2ydx2=2bx3\dfrac{d^2y}{dx^2}=\dfrac{2b}{x^3}. Substitute into xd2ydx2+2dydxx\dfrac{d^2y}{dx^2}+2\dfrac{dy}{dx}: x⋅2bx3+2(−bx2)=2bx2−2bx2=0x\cdot\dfrac{2b}{x^3}+2\left(-\dfrac{b}{x^2}\right)=\dfrac{2b}{x^2}-\dfrac{2b}{x^2}=0 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.