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Exercise 6.3 · Q48

Q.Find the particular solution: cos⁡(dydx)=a, a∈[1,2], y(0)=2\cos\left(\dfrac{dy}{dx}\right)=a,\ a\in[1,2],\ y(0)=2.

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cos⁡(dydx)=a\cos\left(\dfrac{dy}{dx}\right)=a with a∈[1,2]a\in[1,2]. Since cos⁡(⋅)\cos(\cdot) only ever takes values in [−1,1][-1,1], the only value of aa in [1,2][1,2] for which this equation can have any real solution at all is a=1a=1. Then cos⁡(dydx)=1⇒dydx=0\cos\left(\dfrac{dy}{dx}\right)=1\Rightarrow\dfrac{dy}{dx}=0 (the simplest branc …

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