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Exercise 6.3 · Q44

Q.Find the particular solution: (x−y2x)⋅dx−(y+x2y)⋅dy=0(x-y^2x)\cdot dx-(y+x^2y)\cdot dy=0, when x=2, y=0x=2,\ y=0.

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(x−y2x)dx−(y+x2y)dy=0(x-y^2x)dx-(y+x^2y)dy=0 factors as x(1−y2)dx=y(1+x2)dyx(1-y^2)dx=y(1+x^2)dy, which separates as x dx1+x2=y dy1−y2\dfrac{x\,dx}{1+x^2}=\dfrac{y\,dy}{1-y^2}. Integrating: 12log⁡(1+x2)=−12log⁡(1−y2)+c1\tfrac12\log(1+x^2)=-\tfrac12\log(1-y^2)+c_1, i.e. $(1+x^2)(1-y^2) …

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