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Miscellaneous Exercise 7 · Q86

Q.A chemical company produces a chemical containing three basic elements A, B, C so that it has at least 16 liters of A, 24 liters of B and 18 liters of C. This chemical is made by mixing two compounds I and II. Each unit of compound I has 4 liters of A, 12 liters of B, 2 liters of C. Each unit of compound II has 2 liters of A, 2 liters of B and 6 liters of C. The cost per unit of compound I is Rs.800/- and that of compound II is Rs.640/-. Formulate the problem as L.P.P. and solve it to minimize the cost.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Let xx = units of compound I and yy = units of compound II mixed. Element A: 4x+2y≥164x+2y\ge16; Element B: 12x+2y≥2412x+2y\ge24; Element C: 2x+6y≥182x+6y\ge18.

The L.P.P. is — Minimize: z=800x+640yz=800x+640y subject to 4x+2y≥16, 12x+2y≥24, 2x+6y≥18, x≥0, y≥04x+2y\ge16,\ 12x+2y\ge24,\ 2x+6y\ge18,\ x\ge0,\ y\ge0 (and non-negativity).

Drawing the boundary lines and shading the feasible region, its corner points are evaluated in zz:

Corner point (x,y)(x,y)zz
(0, 12)7680
(1, 6)4640
(3, 2)3680
(9, 0)7200

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