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Miscellaneous Exercise 7 · Q56

Q.The corner points of the feasible solution given by the inequation x+y≤4, 2x+y≤7, x≥0, y≥0x + y \le 4,\ 2x + y \le 7,\ x \ge 0,\ y \ge 0 are _______. A) (0, 0), (4, 0), (7, 1), (0, 4)
B) (0, 0), (72,0)\left(\dfrac{7}{2}, 0\right), (3, 1), (0, 4)
C) (0, 0), (72,0)\left(\dfrac{7}{2}, 0\right), (3, 1), (0, 7)
D) (0, 0), (4, 0), (3, 1), (0, 7)

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For x+y≤4, 2x+y≤7, x≥0, y≥0x+y\le4,\ 2x+y\le7,\ x\ge0,\ y\ge0: the x-intercept of 2x+y=72x+y=7 is (72,0)\left(\tfrac72,0\right) (not (4,0)(4,0), since at x=4x=4 the point (4,0)(4,0) fails 2x+y≤72x+y\le7 as 8>78>7); the y-intercept of x+y=4x+y=4 is (0,4)(0,4) (not (0,7)(0,7)); and solving x+y=4, 2x+y=7x+y=4,\ 2x+y=7 simultaneously gives x=3,y=1x=3,y=1. So the four vertices are $ …

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