Skip to content
Miscellaneous Exercise 2(B) II · Q91

Q.Express the following equation in matrix form and solve them by the method of reduction. x−y+z=1, 2x−y=1, 3x+3y−4z=2x-y+z=1,\ 2x-y=1,\ 3x+3y-4z=2

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
75% · 91/121 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: x−y+z=1, 2x−y=1, 3x+3y−4z=2x-y+z=1,\ 2x-y=1,\ 3x+3y-4z=2 becomes [1−112−1033−4][xyz]=[112]\begin{bmatrix}1&-1&1\\2&-1&0\\3&3&-4\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}1\\1\\2\end{bmatrix}.

Step 2: Use R2→R2−2R1R_2\to R_2-2R_1: row 2 becomes (0,1,−2)(0,1,-2), constant becomes 1−2(1)=−11-2(1)=-1. Use R3→R3−3R1R_3\to R_3-3R_1: row 3 becomes (0,6,−7)(0,6,-7), constant becomes 2−3(1)=−12-3(1)=-1.

Step 3: [1−1101−206−7][xyz]=[1−1−1]\begin{bmatrix}1&-1&1\\0&1&-2\\0&6&-7\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}1\\-1\\-1\end{bmatrix}. Use R3→R3−6R2R_3\to R_3-6R_2: row 3 becomes (0,0,−7+12)=(0,0,5)(0,0,-7+12)=(0,0,5), constant becomes −1−6(−1)=5-1-6(-1)=5. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.