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Miscellaneous Exercise 2(B) II · Q98

Q.The cost of 4 pencils, 3 pens and 2 books is Rs. 150. The cost of 1 pencil, 2 pens and 3 books is Rs. 125. The cost of 6 pencils, 2 pens and 3 books is Rs. 175. Find the cost of each item by using Matrices.

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Step 1: Let the costs of one pencil, one pen, one book be Rs. x,y,zx,y,z. "4 pencils, 3 pens, 2 books = Rs. 150": 4x+3y+2z=1504x+3y+2z=150. "1 pencil, 2 pens, 3 books = Rs. 125": x+2y+3z=125x+2y+3z=125. "6 pencils, 2 pens, 3 books = Rs. 175": 6x+2y+3z=1756x+2y+3z=175.

Step 2: Matrix form: [432123623][xyz]=[150125175]\begin{bmatrix}4&3&2\\1&2&3\\6&2&3\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}150\\125\\175\end{bmatrix}.

Step 3: ∣A∣|A|, expanding along row 1: 4(2⋅3−3⋅2)−3(1⋅3−3⋅6)+2(1⋅2−2⋅6)=4(0)−3(−15)+2(−10)=0+45−20=254(2\cdot3-3\cdot2)-3(1\cdot3-3\cdot6)+2(1\cdot2-2\cdot6)=4(0)-3(-15)+2(-10)=0+45-20=25.

Step 4: Computing all nine cofactors and transposing gives adj A=[0−55150−10−10105]\text{adj}\,A=\begin{bmatrix}0&-5&5\\15&0&-10\\-10&10&5\end{bmatrix}, so A−1=125[0−55150−10−10105]A^{-1}=\dfrac{1}{25}\begin{bmatrix}0&-5&5\\15&0&-10\\-10&10&5\end{bmatrix}. …

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