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Miscellaneous Exercise 2(B) II · Q102

Q.The sum of the costs of one book each of Mathematics, Physics and Chemistry is Rs. 210. Total cost of a mathematics book, 2 physics books, and a chemistry book is Rs. 240/-. Also the total cost of a Mathematics book, 3 physics books and 2 chemistry books is Rs. 300/-. Find the cost of each book, using Matrices.

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Step 1: Let the costs of one Mathematics, one Physics, one Chemistry book be Rs. x,y,zx,y,z. "Sum of the three costs is Rs. 210": x+y+z=210x+y+z=210. "1 Maths + 2 Physics + 1 Chemistry = Rs. 240": x+2y+z=240x+2y+z=240. "1 Maths + 3 Physics + 2 Chemistry = Rs. 300": x+3y+2z=300x+3y+2z=300.

Step 2: Matrix form: [111121132][xyz]=[210240300]\begin{bmatrix}1&1&1\\1&2&1\\1&3&2\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}210\\240\\300\end{bmatrix}.

Step 3: Use R2→R2−R1R_2\to R_2-R_1: row 2 becomes (0,1,0)(0,1,0), constant 240−210=30240-210=30. Use R3→R3−R1R_3\to R_3-R_1: row 3 becomes (0,2,1)(0,2,1), constant 300−210=90300-210=90. …

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