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Miscellaneous Exercise 2(B) II · Q94

Q.Express the following equation in matrix form and solve them by the method of reduction. x+y+z=6, 3x−y+3z=10x+y+z=6,\ 3x-y+3z=10 and 5x+5y−4z=35x+5y-4z=3

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Step 1: x+y+z=6, 3x−y+3z=10, 5x+5y−4z=3x+y+z=6,\ 3x-y+3z=10,\ 5x+5y-4z=3 becomes [1113−1355−4][xyz]=[6103]\begin{bmatrix}1&1&1\\3&-1&3\\5&5&-4\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}6\\10\\3\end{bmatrix}.

Step 2: Use R2→R2−3R1R_2\to R_2-3R_1: row 2 becomes (0,−4,0)(0,-4,0), constant 10−18=−810-18=-8. Use R3→R3−5R1R_3\to R_3-5R_1: row 3 becomes (0,0,−9)(0,0,-9), constant 3−30=−273-30=-27. …

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