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Exercise 4.2 · Q29

Q.Find the measure of the acute angle between the lines represented by: 3x2−43xy+3y2=03x^2 - 4\sqrt{3}xy + 3y^2 = 0.

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Here a=3,h=−23,b=3a=3,h=-2\sqrt3,b=3: h2−ab=12−9=3h^2-ab=12-9=3. $\tan\theta=\dfrac{2\sqrt3}{6}=\dfrac{1}{\sqrt3} \Rightarrow \theta= …

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