Worked Examples · Example 6.2
Q.A closed pipe and an open pipe have the same length. Show that no mode of the closed pipe has the same wavelength as any mode of the open pipe.
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Start your 14-day free trial to unlock the full solution →Closed λᶜₚ = 4L/(2p+1); open λᵒₘ = 2L/(m+1). Setting them equal needs 2(m+1) = 2p+1, i.e. even = odd, which is impossible.
For a closed pipe the allowed frequencies are nᶜₚ = (2p+1)nᶜ with nᶜ = v/4L, so the wavelengths are
For an open pipe nᵒₘ = (m+1)nᵒ with nᵒ = v/2L, so
If a closed mode had the same wavelength as an open mode,
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