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Q.A transverse wave is produced on a stretched string 0.9 m long and fixed at its ends. Find the speed of the transverse wave, when the string vibrates while emitting second overtone of frequency 324 Hz.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 2mImportance★★★★★
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For a string fixed at both ends, the nn-th harmonic (second overtone = 3rd harmonic) has frequency fn=nv2Lf_n = \dfrac{nv}{2L}.

For a string of length LL fixed at both ends, the allowed (stationary-wave) frequencies are

fn=nv2L,n=1,2,3,…f_n = \frac{nv}{2L}, \qquad n = 1, 2, 3, \dots

where n=1n=1 is the fundamental, n=2n=2 the first overtone, and n=3n=3 the second overtone.

Given: L=0.9 mL = 0.9\ \text{m}, second overtone frequency f3=324 Hzf_3 = 324\ \text{Hz}, so n=3n=3:

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