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Question 77 of 80

Q.Obtain an expression for practical determination of end correction –

(i) for a pipe open at both ends and
(ii) for a pipe closed at one end.
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
96% · 77/80 Questions
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The end correction is found experimentally by comparing the resonating air-column lengths for two successive resonances (or overtones) with the known wavelength.

  1. Pipe closed at one end (resonance tube method): In a resonance tube (closed pipe) experiment, if L1L_1 and L2L_2 are the lengths of the air column for the first and second resonances with a tuning fork of wavelength λ\lambda, then, because of the end correction ee at the open end, L1+e=λ4,L2+e=3λ4L_1 + e = \dfrac{\lambda}{4}, \qquad L_2 + e = \dfrac{3\lambda}{4} Subtracting: L2−L1=λ2⇒λ=2(L2−L1)L_2 - L_1 = \dfrac{\lambda}{2} \Rightarrow \lambda = 2(L_2-L_1) (this itself is used to find the speed of sound). Also, from the two equations, 3(L1+e)=L2+e  ⇒  3L1+3e=L2+e  ⇒  e=L2−3L123(L_1+e) = L_2+e \;\Rightarrow\; 3L_1 + 3e = L_2 + e \;\Rightarrow\; e = \dfrac{L_2-3L_1}{2}
  2. Pipe open at both ends: For an open pipe, there is an end correction ee at each open end. If LL is the geometrical length and fnf_n the frequency of the nthn^{th} harmonic, fn=nv2(L+2e)f_n = \dfrac{nv}{2(L+2e)} …

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