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Question 74 of 80

Q.Derive an expression for equation of stationary wave on a stretched string. Show that the distance between two successive nodes or antinodes is λ/2.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2024Subjective· 3mImportance★★★★★
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Superposition of two oppositely-travelling identical waves gives a stationary wave.

Consider two identical waves of equal amplitude and frequency travelling in opposite directions along a stretched string (e.g. an incident wave and its reflection):

y1=Asin⁡(kx−ωt),y2=Asin⁡(kx+ωt)y_1 = A\sin(kx-\omega t), \qquad y_2 = A\sin(kx+\omega t)

By superposition, y=y1+y2y = y_1+y_2. Using sin⁡C+sin⁡D=2sin⁡(C+D2)cos⁡(C−D2)\sin C+\sin D = 2\sin\left(\dfrac{C+D}{2}\right)\cos\left(\dfrac{C-D}{2}\right):

y=2Asin⁡(kx)cos⁡(ωt)y = 2A\sin(kx)\cos(\omega t)

This represents a stationary wave: each point xx oscillates with amplitude 2Asin⁡(kx)2A\sin(kx) (fixed in space) and the same time-dependence cos⁡(ωt)\cos(\omega t) everywhere — the waveform does not travel.

Nodes (zero amplitude, always at rest): sin⁡(kx)=0⇒kx=0,π,2π,⋯⇒x=0,λ2,λ,…\sin(kx)=0 \Rightarrow kx = 0,\pi,2\pi,\dots \Rightarrow x = 0,\dfrac{\lambda}{2},\lambda,\dots …

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