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Q.If the tension in sonometer wire is increased by 21%, compare the initial frequency with the later.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 1mImportance★★★★★
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Frequency of a stretched string ∝T\propto \sqrt{T}; a 21% increase in tension gives a 1.21=1.1×\sqrt{1.21}=1.1\times increase in frequency.

For a sonometer wire, the frequency of vibration is related to tension by:

f∝Tf \propto \sqrt{T}

If tension increases by 21%, the new tension is T′=1.21 TT' = 1.21\,T. Then:

f′f=T′T=1.21=1.1\frac{f'}{f} = \sqrt{\frac{T'}{T}} = \sqrt{1.21} = 1.1

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