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Questions 4-12 · Q9

Q.An ideal monatomic gas is adiabatically compressed so that its final temperature is twice its initial temperature. What is the ratio of the final pressure to its initial pressure?

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Step 1. For a monatomic ideal gas, γ=5/3\gamma = 5/3 (Section 4.7.3.5).

Step 2. For an adiabatic process, combining pVγ=constpV^{\gamma} = \text{const} with the ideal gas law gives the relation T2T1=(P2P1)(γ−1)/γ\dfrac{T_2}{T_1} = \left(\dfrac{P_2}{P_1}\right)^{(\gamma-1)/\gamma}.

Step 3. Here γ−1γ=2/35/3=25=0.4\dfrac{\gamma - 1}{\gamma} = \dfrac{2/3}{5/3} = \dfrac{2}{5} = 0.4, and T2/T1=2T_2/T_1 = 2 (final temperature is twice the initial), so 2=(P2P1)0.42 = \left(\dfrac{P_2}{P_1}\right)^{0.4}. …

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