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Question 55 of 68

Q.An ideal mono-atomic gas is adiabatically compressed so that its final temperature is twice its initial temperature. Calculate the ratio of final pressure to its initial pressure.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 2mImportance★★★★★
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Adiabatic relation between T and P, using γ=5/3\gamma=5/3 for a monoatomic gas.

For an adiabatic process, TP(1−γ)/γ=constantTP^{(1-\gamma)/\gamma} = \text{constant}, i.e.

T2T1=(P2P1)(γ−1)/γ\frac{T_2}{T_1} = \left(\frac{P_2}{P_1}\right)^{(\gamma-1)/\gamma}

For a monoatomic ideal gas, γ=5/3\gamma = 5/3, so (γ−1)/γ=(2/3)/(5/3)=2/5(\gamma-1)/\gamma = (2/3)/(5/3) = 2/5.

Given T2=2T1T_2 = 2T_1: …

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