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Exercise 3 · Q7

Q.In what ratio, water must be added to dilute honey costing ₹240 per litre so that the resulted syrup would be worth ₹200 per l?

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Treating water as costing ₹0, alligation gives water : honey =(240−200):(200−0)=1:5=(240-200):(200-0)=1:5.

Rule of alligation:

Qty of waterQty of honey=C.P. of honey−Mean priceMean price−C.P. of water\frac{\text{Qty of water}}{\text{Qty of honey}}=\frac{\text{C.P. of honey}-\text{Mean price}}{\text{Mean price}-\text{C.P. of water}}

Water is free, so its cost price =₹0=\text{₹}0.

  1. Given: honey price =₹240=\text{₹}240/l, water price =₹0=\text{₹}0/l, mean (syrup) price =₹200=\text{₹}200/l. …

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