Skip to content
Exercise 3 · Q6

Q.600 gm of jaggery syrup has 40% jaggery in it. How much jaggery should be added to make it 50% in the syrup?

Puducherry CbseNCERTSubjective· 3mImportance★★★★★
79% · 84/106 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The syrup contains 240240 g of jaggery; adding xx g and requiring 240+x600+x=0.5\dfrac{240+x}{600+x}=0.5 gives x=120x=120 g.

Concentration relation:

Jaggery contentTotal syrup=required fraction\frac{\text{Jaggery content}}{\text{Total syrup}}=\text{required fraction}

Let xx = grams of pure jaggery to add.

  1. Initial jaggery: 40%40\% of 600=40100×600=240600=\dfrac{40}{100}\times 600=240 g.
  2. After adding xx g jaggery: jaggery =240+x=240+x, total =600+x=600+x.
  3. Set to 50%50\%: 240+x600+x=12\dfrac{240+x}{600+x}=\dfrac{1}{2}. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.