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Worked Examples · Example 19

Q.A retailer has 250 kg of rice, a part of which he sells at 10% profit. The remaining quantity of rice is of low quality and he sold it at 5% loss. Overall he made a profit of 7%. Find the quantity of rice sold at 5% loss.

Puducherry CbseNCERTSubjective· 3mImportance★★★★★
18% · 19/106 Questions
✓ Free question

By the rule of alligation on the profit percentages, the profit-part and loss-part are in the ratio 4:14:1, so the loss quantity is 15×250=50\tfrac{1}{5}\times 250=50 kg.

Rule of alligation (for two mixed portions with a common mean):

Quantity at higher rateQuantity at lower rate=Mean−Lower rateHigher rate−Mean\frac{\text{Quantity at higher rate}}{\text{Quantity at lower rate}}=\frac{\text{Mean}-\text{Lower rate}}{\text{Higher rate}-\text{Mean}}

Here the "rates" are the profit percentages: higher =+10%=+10\%, lower =−5%=-5\%, mean =+7%=+7\%.

  1. Let the quantity sold at 10%10\% profit be q1q_1 and at 5%5\% loss be q2q_2, with q1+q2=250q_1+q_2=250 kg.
  2. Apply alligation with rates +10+10, −5-5 and mean +7+7:

q1q2=7−(−5)10−7=123=41.\frac{q_1}{q_2}=\frac{7-(-5)}{10-7}=\frac{12}{3}=\frac{4}{1}.

  1. So q1:q2=4:1q_1:q_2=4:1, giving 55 equal parts in total.
  2. Value of one part =2505=50=\dfrac{250}{5}=50 kg.
  3. Quantity sold at 5%5\% loss =q2=1×50=50=q_2=1\times 50=50 kg.
  4. Check: q1=200q_1=200 kg. Overall profit =200(10)+50(−5)250=2000−250250=1750250=7%=\dfrac{200(10)+50(-5)}{250}=\dfrac{2000-250}{250}=\dfrac{1750}{250}=7\%. ✓
✓Final answer

Quantity of rice sold at 5%5\% loss =50 kg=\mathbf{50\ \text{kg}} (and 200200 kg sold at 10%10\% profit).

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