Question 70 of 71
Q.Calculate the entropy change during the melting of ice into water at 0°C and 1 atm pressure. Enthalpy of fusion of ice is 6008 J mol^-1.
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2026Subjective· 2mImportance★★★★★est
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Start your 14-day free trial to unlock the full solution →We are to calculate the entropy change when ice melts to water at 0°C (273 K) and 1 atm, given the enthalpy of fusion.
ΔS = ΔHfus / T = 6008 / 273 ≈ 22.0 J K^-1 mol^-1 (a positive value, since melting increases disorder).
Melting of ice at its normal melting point (0°C = 273 K) is a reversible phase change occurring at constant temperature and pressure. For such a process, the entropy change is:
ΔS = q(rev) / T = ΔHfus / T
Given: ΔHfus = 6008 J mol^-1 and T = 0°C = 273 K.
ΔS = 6008 J mol^-1 / 273 K = 22.01 J K^-1 mol^-1. …
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