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Chemistry · Class 11 Science

Ch 11Fundamentals of Organic Chemistry — Class 11 Chemistry, concept-first.

Organic chemistry is the study of the compounds of carbon. No other element comes close to carbon's ability to build compounds with itself and with hydrogen, oxygen, nitrogen, sulphur and the halogens -- carbon's defining talent is catenation, the tendency of an atom to chain with atoms of its own element, and catenati…

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Introduction

Organic chemistry is the study of the compounds of carbon. No other element comes close to carbon's ability to build compounds with itself and with hydrogen, oxygen, nitrogen, sulphur and the halogens…

11.2

Classification of Organic Compounds

With millions of organic compounds known and the number growing constantly, classifying them is not optional -- it is the only practical way to organise the subject.

11.2.1

Classification Based on Structure

Structurally, every organic compound is either acyclic (an open, unbranched-or-branched chain, also called aliphatic) or cyclic (containing at least one ring).

11.2.2

Classification Based on Functional Groups

The second way to classify an organic compound is by its functional group -- the reactive atom or group of atoms that gives the molecule its characteristic chemistry, independent of how long or short…

11.3

Nomenclature of Organic Compounds

Before the IUPAC (International Union of Pure and Applied Chemistry) system existed, organic compounds were named ad hoc, and many of those old common names (acetic acid, urea, acetone) are still in e…

11.3.1

IUPAC Rules for Nomenclature of Organic Compounds

Turning the three-piece prefix + root + suffix pattern into an actual working procedure needs two more pieces of machinery: the suffix system, and a five-step naming method.

11.3.2

Nomenclature of Aromatic Compounds

Aromatic compounds are conventionally described in two parts: the nucleus (the benzene ring itself, drawn as a hexagon with alternating double bonds, a circle inside a hexagon, or explicitly as six CH…

11.3.3

Worked Examples of IUPAC Nomenclature

The clearest way to see the IUPAC system actually working is to watch a finished name come apart into its four building blocks -- prefix (with its locants), root word, primary suffix and secondary suf…

11.4

Structural Representation of Organic Compounds

Because the source textbook prints this section's own heading as '11.2 Structural representation of organic compounds' -- reusing the number already assigned to the Classification section earlier in t…

11.4.1

Molecular Models

Because a bond-line drawing is still only a flat, two-dimensional stand-in for a genuinely three-dimensional molecule, chemists also build physical molecular models -- made of wood, plastic or metal,…

11.4.2

Three-Dimensional Representation -- Wedge Formula

The simplest way to recover genuine three-dimensional information from a flat page is the solid-and-dashed wedge convention.

11.4.3

Fischer Projection Formula

The Fischer projection is a specific convention for flattening a three-dimensional structure -- particularly one with one or more chiral (stereogenic) centres -- onto two dimensions, drawn as a cross…

11.4.4

Sawhorse Projection Formula

The sawhorse projection draws the carbon-carbon bond of interest diagonally across the page, slightly elongated, rather than head-on.

11.4.5

Newman Projection Formula

The Newman projection takes a different vantage point again: it looks straight down the carbon-carbon bond axis itself, end-on, so the two bonded carbons visually overlap.

11.5

Isomerism in Organic Compounds

Berzelius coined the term 'isomerism' for a phenomenon that turns out to be central to almost everything else in organic chemistry: two or more compounds can share EXACTLY the same molecular formula w…

11.5.1

Constitutional (Structural) Isomers

Constitutional isomers share a molecular formula but differ in their actual bonding SEQUENCE, and this section works through five named varieties (a sixth, tautomerism, is developed on its own in the…

11.5.2

Tautomerism

Tautomerism is a special, dynamic case of functional isomerism: rather than being two permanently separate compounds, a SINGLE compound exists as two structures -- its tautomers -- that continuously a…

11.5.3

Stereoisomerism

Stereoisomers are, by definition, isomers that share IDENTICAL bond connectivity -- exactly the same atoms bonded to exactly the same other atoms -- and differ only in how their groups or atoms are ar…

11.5.4

Geometrical Isomerism

Geometrical isomerism is a form of stereoisomerism arising specifically from RESTRICTED ROTATION -- either about a carbon-carbon double bond, or about a single bond that happens to be locked inside a…

11.5.5

Optical Isomerism

Optical isomers are a genuinely unusual case: two compounds that are IDENTICAL in every physical and chemical property EXCEPT one -- the direction in which each rotates the plane of plane-polarised li…

11.6

Detection of Elements in Organic Compounds

Before an organic compound's structure can be worked out, the very first analytical step is simply finding out WHICH elements it contains -- this is qualitative elemental analysis, distinct from (and…

11.6.1

Detection of Carbon and Hydrogen

If a substance is already known (or strongly suspected) to be organic, there is technically no need to separately confirm the presence of carbon -- the carbon test in this section exists mainly as a w…

11.6.2

Detection of Nitrogen, Sulphur, Halogens and Phosphorus -- Lassaigne's Test

Lassaigne's sodium fusion test is the standard, general-purpose method for detecting nitrogen (in any class of nitrogen-containing compound), sulphur and the halogens all from one preparation.

11.7

Estimation of Elements

Detecting which elements a compound contains (the previous section) only answers a yes/no question for each element; the natural next question is HOW MUCH of each element is actually present, by weigh…

11.7.1

Estimation of Carbon and Hydrogen

Carbon and hydrogen are always estimated together, by the same underlying combustion method: a precisely known weight of the organic substance is burnt completely in an excess of oxygen, converting ev…

11.7.2

Estimation of Sulphur -- Carius Method

Sulphur is estimated by the Carius method: a precisely known mass of the organic substance is heated strongly, in a sealed tube, together with fuming nitric acid.

11.7.3

Estimation of Halogens -- Carius Method

Halogens are estimated by a variant of the same Carius method used for sulphur: a known mass of the organic compound is heated, sealed in a Carius tube, together with BOTH fuming nitric acid AND silve…

11.7.4

Estimation of Phosphorus -- Carius Method

Phosphorus is estimated by yet another variant of the Carius method: a known mass (w) of the phosphorus-containing organic compound is heated, sealed in a tube, with fuming nitric acid, again oxidisin…

11.7.5

Estimation of Nitrogen -- Dumas Method

The Dumas method estimates nitrogen directly, as a gas, and rests on one core fact: heating a nitrogenous organic compound together with cupric oxide, IN AN ATMOSPHERE OF CARBON DIOXIDE, converts ever…

11.7.6

Estimation of Nitrogen -- Kjeldahl's Method

Kjeldahl's method is the more commonly used of the two nitrogen-estimation methods precisely because it is easier to carry out than Dumas's, and it sees heavy practical use in the routine analysis of…

11.8

Purification of Organic Compounds

Studying an organic compound's true structure, and measuring its real physical, chemical and biological properties, only makes sense once the compound itself is genuinely PURE -- any lingering impurit…

11.8.1

Sublimation

A small handful of solid substances -- benzoic acid, naphthalene and camphor are the standard examples -- pass DIRECTLY from the solid state to vapour when heated, without ever passing through a liqui…

11.8.2

Crystallization

Crystallisation is the single most widely used method for purifying a SOLID organic compound, and it proceeds through four distinct stages.

11.8.3

Distillation

Distillation as a family of techniques purifies LIQUIDS -- either by separating a liquid from a non-volatile impurity, or by separating the individual components of a liquid MIXTURE whose components d…

11.8.4

Steam Distillation

Steam distillation is applicable to both solid and liquid organic compounds, but only under a specific set of conditions: the compound must not decompose at the temperature of steam, it must have a fa…

11.8.5

Azeotropic Distillation

Some liquid mixtures resist separation by fractional distillation altogether, however carefully it is carried out -- these are azeotropes, mixtures that boil at one single, CONSTANT temperature and di…

11.8.6

Differential Extraction

Extraction, in general, is the process of pulling a dissolved substance OUT of an aqueous solution by shaking that solution together with a suitable organic solvent that the substance is more soluble…

11.8.7

Chromatography

Chromatography is the single most valuable technique available for separating and purifying very SMALL quantities of a mixture -- exactly the situation where crystallisation or distillation would stru…

Sample & Board Papers

Sample papers and previous-year board questions for this subject.

+Show 20 questions20 questions
  1. Q1Which one of the following method is used to estimate Nitrogen? (a) Kjeldahl method (b) Carius method (c) Lassaigne's test (d) Liebig's comb…Preview
  2. Q2Purification of mixture of compounds can be done by steam distillation only if the impurities are ________. (a) non - volatile (b) volatile…Preview
  3. Q3Explain the fractional distillation method of purification.Preview
  4. Q4(i) How will you estimate oxygen? [2 marks] (ii) Explain about Carius method of estimation of sulphur. [3 marks] **OR** Explain the mechanis…Preview
  5. Q5Many of the organic compounds are inflammable because of its: (a) Vander Waal's force (b) Co-ordinate nature (c) Covalent nature (d) Ionic n…Preview
  6. Q6Describe the reaction involved in the detection of Nitrogen in an organic compound by Lassaigne Method.Preview
  7. Q7Which is the suitable method for detection of Nitrogen present in food and fertilizers?Preview
  8. Q8(i) Write the IUPAC name for the following compounds. (A) CH3-CH(CH3)-CH2-CH3 (B) H3C-C(CH3)(CH3)-CH3 (a central carbon bonded to four CH3 g…Preview
  9. Q9Write the IUPAC name of CH3-CH2-CH(OH)-CHO. (a) 1-formyl propanol (b) 1-hydroxy butanal (c) 2-hydroxy butanal (d) 3-hydroxy butanalPreview
  10. Q10Which element exhibits maximum catenation and why?Preview
  11. Q11Match the following: (1) -NO2 (2) -OCH3 (3) -CH2-CH2-CH3 (4) -NH2 with (i) Propyl (ii) Amino (iii) Methoxy (iv) Nitro (a) (1)-(iii), (2)-(ii…Preview
  12. Q12What is meant by optical isomerism?Preview
  13. Q13The IUPAC name of the compound CH3-CH(OH)-CH2-CH=CH-CH3 : (a) hex-2-en-4-ol (b) hex-4-en-2-ol (c) hex-2-en-4-al (d) hex-4-en-2-alPreview
  14. Q14Nitrogen detection in an organic compound is carried out by Lassaigne's test. The blue colour formed in this reaction is due to the formatio…Preview
  15. Q15What is Homologous series?Preview
  16. Q16Which of the following is optically active ? (a) Meso-tartaric acid (b) 3-Chloropentane (c) Glucose (d) 2-Chloro propanePreview
  17. Q17What is Isomerism ? Give its types.Preview
  18. Q18Heterolytic fission of C-C bond results in the formation of : (a) Free radical (b) Carbanion (c) Carbocation (d) Carbanion and CarbocationPreview
  19. Q19Calculate the entropy change during the melting of ice into water at 0°C and 1 atm pressure. Enthalpy of fusion of ice is 6008 J mol^-1.Preview
  20. Q20What type of hybridisation are possible in the following geometries ? (a) Octahedral (b) Tetrahedral (c) Square planarPreview

More questions

51 Q
+Show 30 questions30 questions
  1. Q1Select the molecule which has only one π bond. a) CH3-CH=CH-CH3 b) CH3-CH=CH-CHO c) CH3-CH=CH-COOH d) All of theseFree
  2. Q2In the hydrocarbon CH3-CH2-CH=CH-CH2-C≡CH (numbered 7,6,5,4,3,2,1 from the left CH3 to the terminal ≡CH), the state of hybridisation of carb…Free
  3. Q3The general formula for alkadiene is a) CnH2n b) CnH2n-1 c) CnH2n-2 d) CnHn-2Free
  4. Q4Structure of the compound whose IUPAC name is 5,6-dimethylhept-2-ene is (options a, b, c are hand-drawn skeletal/bond-line structures in the…Preview
  5. Q5The IUPAC name of the compound H3C-CH2-CH(CH3)-CH(CH2CH3)-CH2-CH2-CH2-CH3 (an octane chain bearing a methyl branch on the third carbon and a…Preview
  6. Q6Which one of the following names does not fit a real name? a) 3-Methyl-3-hexanone b) 4-Methyl-3-hexanone c) 3-Methyl-3-hexanol d) 2-Methyl c…Preview
  7. Q7The IUPAC name of the compound CH3-CH=CH-C≡CH is a) Pent-4-yn-2-ene b) Pent-3-en-1-yne c) pent-2-en-4-yne d) Pent-1-yn-3-enePreview
  8. Q8IUPAC name of CH3-CH(C2H5)-C(C4H9)(CH3)-CH3, i.e. CH3-C(H)(C2H5)-C(C4H9)(CH3)-CH3 drawn as a 4-carbon backbone CH3-C-C-CH3 in which the seco…Preview
  9. Q9The IUPAC name of H3C-C(CH3)(CH3)-CH=C(CH3)2 is a) 2,4,4-Trimethylpent-2-ene b) 2,4,4-Trimethylpent-3-ene c) 2,2,4-Trimethylpent-3-ene d) 2,…Preview
  10. Q10The IUPAC name of the compound CH3-CH=C(CH2-CH2-CH3)-CH2-CH3 is a) 3-Ethyl-2-hexene b) 3-Propyl-3-hexene c) 4-Ethyl-4-hexene d) 3-Propyl-2-h…Preview
  11. Q11The IUPAC name of CH3-CH(OH)-COOH is a) 2-Hydroxypropionic acid b) 2-Hydroxy Propanoic acid c) Propan-2-ol-1-oic acid d) 1-CarboxyethanolPreview
  12. Q12The IUPAC name of (CH3)(Br)CH-CH(CH3)-COOH, i.e. CH3-CH(Br)-CH(CH3)-COOH, is a) 2-Bromo-3-methylbutanoic acid b) 2-methyl-3-bromobutanoic ac…Preview
  13. Q13The structure of isobutyl group in an organic compound is a) CH3-CH2-CH2-CH2- b) CH3-C(CH3)(CH3)- [tert-butyl, i.e. CH3 with two more CH3 br…Preview
  14. Q14The number of stereoisomers of 1,2-dihydroxycyclopentane a) 1 b) 2 c) 3 d) 4Preview
  15. Q15Which of the following is optically active? a) 3-Chloropentane b) 2-Chloropropane c) Meso-tartaric acid d) GlucosePreview
  16. Q16The isomer of ethanol is a) acetaldehyde b) dimethylether c) acetone d) methyl carbinolPreview
  17. Q17How many cyclic and acyclic isomers are possible for the molecular formula C3H6O? a) 4 b) 5 c) 9 d) 10Preview
  18. Q18Which one of the following shows functional isomerism? a) ethylene b) Propane c) ethanol d) CH2Cl2Preview
  19. Q19CH2=C(-O⁻)-CH3 and ⁻CH2-C(=O)-CH3 (two resonance-type structures of the acetone enolate anion, differing only in whether the negative charge…Preview
  20. Q20Nitrogen detection in an organic compound is carried out by Lassaigne's test. The blue colour formed is due to the formation of a) Fe3[Fe(CN…Preview
  21. Q21Lassaigne's test for the detection of nitrogen fails in a) H2N-CO-NH-NH2.HCl b) NH2-NH2.HCl c) C6H5-NH-NH2.HCl d) C6H5CONH2Preview
  22. Q22Connect the pair of compounds which give blue colouration/precipitate and white precipitate respectively, when their Lassaigne's test is sep…Preview
  23. Q23Sodium nitroprusside reacts with sulphide ion to give a purple colour due to the formation of a) [Fe(CN)5NO]3- b) [Fe(NO)5CN]+ c) [Fe(CN)5NO…Preview
  24. Q24An organic compound weighing 0.15 g gave, on carius estimation, 0.12 g of silver bromide. The percentage of bromine in the compound will be…Preview
  25. Q25A sample of 0.5 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO…Preview
  26. Q26In an organic compound, phosphorus is estimated as a) Mg2P2O7 b) Mg3(PO4)2 c) H3PO4 d) P2O5Preview
  27. Q27Ortho and para-nitrophenol can be separated by a) azeotropic distillation b) destructive distillation c) steam distillation d) cannot be sep…Preview
  28. Q28The purity of an organic compound is determined by a) Chromatography b) Crystallisation c) melting or boiling point d) both (a) and (c)Preview
  29. Q29A liquid which decomposes at its boiling point can be purified by a) distillation at atmospheric pressure b) distillation under reduced pres…Preview
  30. Q30Assertion: CH3-C(COOC2H5)=CH-COOH is 3-carbethoxy-2-butenoic acid. Reason: The principal functional group gets the lowest number, followed b…Preview
+Show 21 questions21 questions
  1. Q31Give the general characteristics of organic compounds?Free
  2. Q32Describe the classification of organic compounds based on their structure.Free
  3. Q33Write a note on homologous series.Free
  4. Q34What is meant by a functional group? Identify the functional group in the following compounds. (a) acetaldehyde (b) oxalic acid (c) di methy…Preview
  5. Q35Give the general formula for the following classes of organic compounds (a) Aliphatic monohydric alcohol (b) Aliphatic ketones (c) Aliphatic…Preview
  6. Q36Write the molecular formula of the first six members of homologous series of nitro alkanes.Preview
  7. Q37Write the molecular and possible structural formula of the first four members of homologous series of carboxylic acids.Preview
  8. Q38Give the IUPAC names of the following compounds. (i) (CH3)2CH-CH2-CH(CH3)-CH(CH3)2 (ii) CH3-CH(CH3)-CH(Br)-CH3 (iii) CH3-O-CH3 (iv) CH3-CH2-…Preview
  9. Q39Give the structure for the following compounds. (i) 3-ethyl-2-methyl-1-pentene (ii) 1,3,5-Trimethylcyclohex-1-ene (iii) tertiary butyl iodid…Preview
  10. Q40Describe the reactions involved in the detection of nitrogen in an organic compound by Lassaigne's method.Preview
  11. Q41Give the principle involved in the estimation of halogen in an organic compound by carius method.Preview
  12. Q42Give a brief description of the principles of i) Fractional distillation ii) Column ChromatographyPreview
  13. Q43Explain paper chromatographyPreview
  14. Q44Explain various types of constitutional isomerism (structural isomerism) in organic compoundsPreview
  15. Q45Describe optical isomerism with suitable example.Preview
  16. Q46Briefly explain geometrical isomerism in alkene by considering 2-butene as an example.Preview
  17. Q470.30 g of a substance gives 0.88 g of carbon dioxide and 0.54 g of water. Calculate the percentage of carbon and hydrogen in it.Preview
  18. Q48The ammonia evolved from 0.20 g of an organic compound by Kjeldahl method neutralised 15 mL of N/20 sulphuric acid solution. Calculate the p…Preview
  19. Q490.32 g of an organic compound, after heating with fuming nitric acid and barium nitrate crystals in a sealed tube, gave 0.466 g of barium su…Preview
  20. Q500.24 g of an organic compound gave 0.287 g of silver chloride in the carius method. Calculate the percentage of chlorine in the compound.Preview
  21. Q51In the estimation of nitrogen present in an organic compound by Dumas method, 0.35 g yielded 20.7 mL of nitrogen at 15°C and 760 mm pressure…Preview