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Write Brief Answer · Q25

Q.Hydrochloric acid is treated with a metal to produce hydrogen gas. Suppose a student carries out this reaction and collects a volume of 154.4×10−3154.4\times10^{-3} dm3^3 of a gas at a pressure of 742 mm of Hg at a temperature of 298 K. What mass of hydrogen gas (in mg) did the student collect?

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Step 1. Convert the given values to consistent units: V=154.4×10−3 dm3=0.1544 LV=154.4\times10^{-3}\ \text{dm}^3=0.1544\ \text{L}; P=742 mmHg=742760 atm≈0.9763 atmP=742\ \text{mmHg}=\dfrac{742}{760}\ \text{atm}\approx0.9763\ \text{atm}; T=298T=298 K.

Step 2. Use n=PVRTn=\dfrac{PV}{RT} with R=0.0821 dm3 atm K−1mol−1R=0.0821\ \text{dm}^3\,\text{atm}\,\text{K}^{-1}\text{mol}^{-1}: n=0.9763×0.15440.0821×298=0.150824.466≈0.006163 moln=\dfrac{0.9763\times0.1544}{0.0821\times298}=\dfrac{0.1508}{24.466}\approx0.006163\ \text{mol}. …

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