Q.Explain geometrical isomerism in 2-butene.
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →2-Butene exists as cis- and trans- geometrical isomers because the C=C double bond prevents free rotation, fixing the two methyl groups either on the same side (cis) or opposite sides (trans).
Geometrical (cis-trans) isomerism arises in alkenes when each of the two double-bonded carbon atoms carries two DIFFERENT groups, and rotation about the C=C bond is restricted (because rotating would require breaking the pi bond). In 2-butene, CH3-CH=CH-CH3, each double-bond carbon is attached to one -CH3 group and one -H atom, which are different from each other on each carbon — satisfying the condition for geometrical isomerism.
Because the double bond is rigid (no free rotation), two distinct spatial arrangements are possible and do not interconvert at ordinary temperatures:
-
cis-2-butene: the two -CH3 groups (the higher-priority/bulkier groups) lie on the SAME side of the double bond, with the two -H atoms on the other side.
-
trans-2-butene: the two -CH3 groups lie on OPPOSITE sides of the double bond (diagonally across from each other), with the -H atoms also on opposite sides.
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.