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Question 62 of 83

Q.Write the no bond resonance structure shown by propene.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2020Subjective· 2mImportance★★★★★
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In propene, one of the C-H sigma bonds of the methyl group (adjacent to the C=C double bond) can delocalise its electron pair into the pi system, giving 'no-bond resonance' structures — this is hyperconjugation.

Hyperconjugation, also historically called 'no-bond resonance', is the stabilising interaction between the electrons of a sigma bond (usually a C-H or C-C bond) and an adjacent empty or pi-type orbital (such as a p-orbital of an adjacent carbocation, radical, or alkene pi-bond).

In propene, CH3-CH=CH2, the methyl group is directly attached to the sp2 carbon of the double bond. One of the three equivalent C-H sigma bonds of this methyl group can align with the pi orbital of the double bond, allowing partial overlap and electron delocalisation. This can be represented by a resonance (canonical) structure in which that particular C-H bond is shown broken, with the electron pair moved into the pi system and the hydrogen atom left attached by 'no bond' (a dangling H+ with a dotted or absent bond line), while a small negative charge appears on the terminal (originally =CH2) carbon:

CH3-CH=CH2 <-> (H2C...H)+-CH=CH2^-

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