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Question 116 of 129

Q.If f′(x)=4x−5f'(x)=4x-5 and f(2)=1f(2)=1, find f(x)f(x).

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2022Subjective· 3mImportance★★★★★
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Integrating f′(x)=4x−5f'(x)=4x-5 and using f(2)=1f(2)=1 to fix the constant gives f(x)=2x2−5x+3f(x)=2x^2-5x+3.

f(x)=∫(4x−5) dx=2x2−5x+Cf(x) = \displaystyle\int(4x-5)\,dx = 2x^2-5x+C.

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