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Question 126 of 129

Q.Integrate with respect to xx : cos⁡5xsin⁡3x\cos 5x \sin 3x

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2025Subjective· 3mImportance★★★★★
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Use the product-to-sum formula sin⁡Acos⁡B=12[sin⁡(A+B)+sin⁡(A−B)]\sin A\cos B=\dfrac12[\sin(A+B)+\sin(A-B)] to turn the product into a sum of sines, then integrate directly.

sin⁡3xcos⁡5x=12[sin⁡(3x+5x)+sin⁡(3x−5x)]=12[sin⁡8x+sin⁡(−2x)]=12[sin⁡8x−sin⁡2x]\sin3x\cos5x=\dfrac12\left[\sin(3x+5x)+\sin(3x-5x)\right]=\dfrac12\left[\sin8x+\sin(-2x)\right]=\dfrac12\left[\sin8x-\sin2x\right]

So …

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