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Question 127 of 129

Q.If ∫f(x)dx=g(x)+c\int f(x)dx = g(x) + c, then ∫f(x) g′(x)dx\int f(x)\, g'(x)dx is:

(a) ∫f′(x) g(x)dx\int f'(x)\, g(x)dx
(b) ∫(f(x))2dx\int (f(x))^2 dx
(c) ∫(g(x))2dx\int (g(x))^2 dx
(d) ∫f(x) g(x)dx\int f(x)\, g(x)dx
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2026MCQ· 1mImportance★★★★★
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Given ∫f(x) dx=g(x)+c\int f(x)\,dx=g(x)+c, differentiating shows g′(x)=f(x)g'(x)=f(x), so ∫f(x)g′(x) dx=∫(f(x))2 dx\int f(x)g'(x)\,dx=\int (f(x))^2\,dx.

Given ∫f(x) dx=g(x)+c\int f(x)\,dx=g(x)+c. Differentiating both sides with respect to xx: f(x)=g′(x)f(x)=g'(x).

Substitute g′(x)=f(x)g'(x)=f(x) into ∫f(x) g′(x) dx\int f(x)\,g'(x)\,dx:

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