Q.Find the point on the curve $y=x^2-5x+4$ at which the tangent is parallel to the line $3x+y=7$.

Tangents and Normals to a Curve

At a point $P(x_1,y_1)$ on $y=f(x)$ with slope $m=\dfrac{dy}{dx}$, the tangent line is

$y-y_1=m(x-x_1)$ and the normal has slope $-\dfrac1m$. Four classical lengths are

measured from $P$ and the foot $A$ of the ordinate on the $x$-axis:

• Length of tangent $=\Big|\dfrac{y_1\sqrt{1+m^2}}{m}\Big|$,
• Length of normal $=\big|y_1\sqrt{1+m^2}\big|$,
• Subtangent $ST=\Big|\dfrac{y_1}{m}\Big|$,
• Subnormal $SN=|m\,y_1|$.

From these, $SN\cdot ST=y_1^2$ and $\dfrac{SN}{ST}=m^2$. For a curve given

parametrically ($x=x(\theta),y=y(\theta)$) the slope is $\dfrac{dy/d\theta}{dx/d\theta}$

and the same length formulas apply. These quantities let one compare tangent, normal,

subtangent and subnormal, or impose relations such as $p\,(SN)=q\,(ST)^2$ on a curve.

Tangents, normals and the related subtangent/subnormal lengths are part of the NCERT/CBSE Class 12 Mathematics "Application of Derivatives" chapter, matching "tangents and normals class 12 maths important questions" searches. These length relationships are a classic JEE Main and CET application-of-derivatives question type.