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Mathematics · Ch 9 — Applications of Integration

Area of the Region Bounded Between Two Curves

9.8.3

Area of the Region Bounded Between Two Curves

Case (i): between two curves, integrating in xx. Let y=f(x)y=f(x) and y=g(x)y=g(x) be curves with f(x)≥g(x)f(x)\ge g(x) for all x∈[a,b]x\in[a,b]. The region bounded between them and the ordinates x=a,x=bx=a,x=b is divided into thin vertical strips of width Δx\Delta x and height f(x)−g(x)≥0f(x)-g(x)\ge0. Summing and passing to the limit,

A=∫ab[f(x)−g(x)] dx.A=\int_a^b\big[f(x)-g(x)\big]\,dx.

Calling y=f(x)y=f(x) the upper curve (UU, viewed in the positive yy-direction) and y=g(x)y=g(x) the lower curve (LL), this is written A=∫ab(yU−yL) dxA=\displaystyle\int_a^b(y_U-y_L)\,dx.

Case (ii): between two curves, integrating in yy. Let x=f(y)x=f(y) and x=g(y)x=g(y) with f(y)≥g(y)f(y)\ge g(y) for all y∈[c,d]y\in[c,d]. Viewing in the positive xx-direction, calling x=f(y)x=f(y) the right curve (RR) and x=g(y)x=g(y) the left curve (LL),

A=∫cd[f(y)−g(y)] dy=∫cd(xR−xL) dy.A=\int_c^d\big[f(y)-g(y)\big]\,dy=\int_c^d(x_R-x_L)\,dy.

General working rule (no need to name curves globally as upper/lower). For a region bounded by y=f1(x)y=f_1(x), y=f2(x)y=f_2(x) and the lines x=a, x=bx=a,\,x=b (a<ba<b): draw an arbitrary vertical line cutting the region; let yENTRYy_{\text{ENTRY}} be the yy-value where the line enters the region and yEXITy_{\text{EXIT}} where it exits (both read off the bounding curves' equations at that xx). Then

A=∫ab[yEXIT−yENTRY] dx.A=\int_a^b\big[y_{\text{EXIT}}-y_{\text{ENTRY}}\big]\,dx.

The mirror rule (region bounded by x=g1(y), x=g2(y)x=g_1(y),\,x=g_2(y) and y=c, y=dy=c,\,y=d, c<dc<d): draw a horizontal line, find xENTRYx_{\text{ENTRY}} and xEXITx_{\text{EXIT}}, and

A=∫cd[xEXIT−xENTRY] dy.A=\int_c^d\big[x_{\text{EXIT}}-x_{\text{ENTRY}}\big]\,dy.

Recurring worked patterns (Examples 9.47-9.61). The area of an ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 is πab\pi ab (circle, b=ab=a: πa2\pi a^2); the area between the parabola y2=4axy^2=4ax and its latus rectum (x=ax=a) is 83a2\frac83a^2 — Archimedes' formula, two-thirds the area of the enclosing rectangle (base = latus rectum, height = distance from vertex to the latus rectum), and equivalently four-thirds the area of the inscribed triangle, exactly the ratio proved in §9.1; a triangle's area can be found purely by integration by writing each side as a line and adding/subtracting the areas under them; and the region between a tangent and normal to a circle can be computed by either vertical or horizontal strips, giving the same value both ways — a useful self-check. …

Figure 9.22Fig. 9.22 — Example 9.53: the region bounded by $y=|\cos x|$, the x-axis and the lines $x=0$, $x=\pi$ (two arches meeting at the cusp $x=\frac{\pi}{2}$)
Fig. 9.22 — Fig. 9.22 — Example 9.53: the region bounded by $y=|\cos x|$, the x-axis and the lines $x=0$, $x=\pi$ (two arches meeting at the cusp $x=\frac{\pi}{2}$)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig. 9.22 — Example 9.53: the region bounded by y=∣cos⁡x∣y=|\cos x|, the x-axis and the lines x=0x=0, x=πx=\pi (two arches meeting at the cusp $x=\f …

Figure 9.23Fig. 9.23 — Area of the region between two curves $y=f(x)$ (upper) and $y=g(x)$ (lower) with $f(x)\ge g(x)$ on $[a,b]$; vertical strip of height $f(x)-g(x)$
Fig. 9.23 — Fig. 9.23 — Area of the region between two curves $y=f(x)$ (upper) and $y=g(x)$ (lower) with $f(x)\ge g(x)$ on $[a,b]$; vertical strip of height $f(x)-g(x)$

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig. 9.23 — Area of the region between two curves y=f(x)y=f(x) (upper) and y=g(x)y=g(x) (lower) with f(x)≥g(x)f(x)\ge g(x) on [a,b][a,b]; vertical strip of heig …

Figure 9.24Schematic of the area bounded between two curves x=f(y) and x=g(y) and the lines y=c and y=d, divided into thin horizontal strips (Case ii integration with respect to y).
Fig. 9.24 — Schematic of the area bounded between two curves x=f(y) and x=g(y) and the lines y=c and y=d, divided into thin horizontal strips (Case ii integration with respect to y).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Schematic of the area bounded between two curves x=f(y) and x=g(y) and the lines y=c and y=d, divided into thin horizontal strips (Case ii integration wit …

Figure 9.25Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin vertical strip; upper boundary y=2 sqrt(x), lower boundary y=x^2/4.
Fig. 9.25 — Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin vertical strip; upper boundary y=2 sqrt(x), lower boundary y=x^2/4.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin vertical strip; upper boundary y=2 sqrt(x), lower b …

Figure 9.26Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin horizontal strip; right boundary x=2 sqrt(y), left boundary x=y^2/4.
Fig. 9.26 — Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin horizontal strip; right boundary x=2 sqrt(y), left boundary x=y^2/4.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the region bounded between the parabolas y^2=4x and x^2=4y from (0,0) to (4,4), shaded with a thin horizontal strip; right boundary x=2 sqrt(y), left b …

Figure 9.27Area of the region bounded between the parabola x^2=y and the curve y=|x|, lying in the first and second quadrants, bounded by y=x and y=-x, shaded with a thin vertical strip.
Fig. 9.27 — Area of the region bounded between the parabola x^2=y and the curve y=|x|, lying in the first and second quadrants, bounded by y=x and y=-x, shaded with a thin vertical strip.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the region bounded between the parabola x^2=y and the curve y=|x|, lying in the first and second quadrants, bounded by y=x and y=-x, shaded with a thin …

Figure 9.28Area of the region bounded by y=cos x and y=sin x between the lines x=pi/4 and x=5pi/4, shaded where sin x is above cos x.
Fig. 9.28 — Area of the region bounded by y=cos x and y=sin x between the lines x=pi/4 and x=5pi/4, shaded where sin x is above cos x.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the region bounded by y=cos x and y=sin x between the lines x=pi/4 and x=5pi/4, shaded where sin x is abo …

Figure 9.29The circle x^2+y^2=a^2 divided into two segments by the line x=h; the smaller segment (to the right of x=h, up to x=a) is shaded.
Fig. 9.29 — The circle x^2+y^2=a^2 divided into two segments by the line x=h; the smaller segment (to the right of x=h, up to x=a) is shaded.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. The circle x^2+y^2=a^2 divided into two segments by the line x=h; the smaller segment (to the right of x=h, up to x=a) …

Figure 9.30Area of the region in the first quadrant bounded by the parabola y^2=4x, the line x+y=3 and the y-axis; intersection points (1,2) and (9,-6) shown.
Fig. 9.30 — Area of the region in the first quadrant bounded by the parabola y^2=4x, the line x+y=3 and the y-axis; intersection points (1,2) and (9,-6) shown.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the region in the first quadrant bounded by the parabola y^2=4x, the line x+y=3 and the y-axis; intersection points (1,2) and ( …

Figure 9.31Area of the triangular region bounded by the lines 5x-2y=15, x+y+4=0 and the x-axis, lying below the x-axis with vertices (3,0), (-4,0) and (1,-5); a horizontal strip of width delta y is shown.
Fig. 9.31 — Area of the triangular region bounded by the lines 5x-2y=15, x+y+4=0 and the x-axis, lying below the x-axis with vertices (3,0), (-4,0) and (1,-5); a horizontal strip of width delta y is shown.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of the triangular region bounded by the lines 5x-2y=15, x+y+4=0 and the x-axis, lying below the x-axis with vertices (3,0), (-4,0) and (1,-5); a horizontal strip of widt …

Figure 9.32Area of triangle ABC with vertices A(-1,1), B(3,2), C(0,5) found by integration, split into region DACO and region OCBE (feet D and E on the x-axis).
Fig. 9.32 — Area of triangle ABC with vertices A(-1,1), B(3,2), C(0,5) found by integration, split into region DACO and region OCBE (feet D and E on the x-axis).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area of triangle ABC with vertices A(-1,1), B(3,2), C(0,5) found by integration, split into region DACO and region OCBE (feet D and E on …

Figure 9.33Area bounded by the x-axis, the tangent and the normal to the circle x^2+y^2=4 drawn at (1,sqrt 3); the tangent meets the x-axis at (4,0) and the normal passes through the origin.
Fig. 9.33 — Area bounded by the x-axis, the tangent and the normal to the circle x^2+y^2=4 drawn at (1,sqrt 3); the tangent meets the x-axis at (4,0) and the normal passes through the origin.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Area bounded by the x-axis, the tangent and the normal to the circle x^2+y^2=4 drawn at (1,sqrt 3); the tangent meets the x-axis at (4,0) and the normal passes th …