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Question 72 of 99

Q.If u=f(x,y)u = f(x, y) is a differentiable function of xx and yy; where xx and yy are differentiable functions of 't' then :

(a) dudt=∂f∂x⋅∂x∂t+∂f∂y⋅∂y∂t\dfrac{du}{dt} = \dfrac{\partial f}{\partial x}\cdot\dfrac{\partial x}{\partial t} + \dfrac{\partial f}{\partial y}\cdot\dfrac{\partial y}{\partial t}
(b) dudt=∂f∂x⋅dxdt+∂f∂y⋅dydt\dfrac{du}{dt} = \dfrac{\partial f}{\partial x}\cdot\dfrac{dx}{dt} + \dfrac{\partial f}{\partial y}\cdot\dfrac{dy}{dt}
(c) dudt=∂f∂x⋅dxdt+∂f∂y⋅dydt\dfrac{du}{dt} = \dfrac{\partial f}{\partial x}\cdot\dfrac{dx}{dt} + \dfrac{\partial f}{\partial y}\cdot\dfrac{dy}{dt}
(d) ∂u∂t=∂f∂x⋅∂x∂t+∂f∂y⋅∂y∂t\dfrac{\partial u}{\partial t} = \dfrac{\partial f}{\partial x}\cdot\dfrac{\partial x}{\partial t} + \dfrac{\partial f}{\partial y}\cdot\dfrac{\partial y}{\partial t}
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Since xx and yy are each functions of the single variable tt, the total derivative chain rule uses ordinary derivatives dx/dtdx/dt and dy/dtdy/dt (not partial derivatives ∂x/∂t\partial x/\partial t), matching option (b)/(c).

  1. u=f(x,y)u=f(x,y) is a differentiable function of two variables x,yx,y, and both x=x(t)x=x(t), y=y(t)y=y(t) are differentiable functions of the single independent variable tt.
  2. Because xx and yy each depend on tt alone (not on tt together with any other independent variable), the rate of change of xx and yy with respect to tt is an ordinary derivative, written dxdt\dfrac{dx}{dt} and dydt\dfrac{dy}{dt} — not a partial derivative ∂x∂t\dfrac{\partial x}{\partial t}, which would only be meaningful if xx depended on tt and some other independent variable simultaneously.
  3. The chain rule for the total derivative of the composite u=f(x(t),y(t))u=f(x(t),y(t)) is therefore: dudt=∂f∂x⋅dxdt+∂f∂y⋅dydt\frac{du}{dt} = \frac{\partial f}{\partial x}\cdot\frac{dx}{dt} + \frac{\partial f}{\partial y}\cdot\frac{dy}{dt}
  4. Options (a) and (d) incorrectly use ∂x∂t\dfrac{\partial x}{\partial t} and ∂y∂t\dfrac{\partial y}{\partial t} in place of the ordinary derivatives, and (d) also incorrectly writes ∂u∂t\dfrac{\partial u}{\partial t} on the left (there is no such partial derivative here, since uu's only route of dependence on tt is through xx and yy) — both are wrong. …

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