Q.In the circuit shown, a battery of emf 15 V (internal resistance negligible) is connected through a resistor carrying current , and a battery of emf 9 V is connected through another resistor carrying current ; both branches meet at a junction and share a third resistor carrying current . Calculate the currents , and in the circuit.
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Start your 14-day free trial to unlock the full solution →Step 1. Take the 15 V battery in series with one resistor (current ) and the 9 V battery in series with a second resistor (current ), both meeting at a junction and continuing together as through the third resistor, , back to both batteries.
Step 2. Applying Kirchhoff's voltage rule to the 15 V loop (through its own and then through ): .
Step 3. Applying Kirchhoff's voltage rule to the 9 V loop (through its own and then through ): .
Step 4. Solving the two simultaneous equations and : multiplying the first by 2 gives ; subtracting the second gives , so A (matching the given answer).
Step 5. Substituting back, , so A in magnitude. …
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