Q.Match the following and choose the correct option from those given below.
Column I: A. Molecular oxygen B. Electron acceptor C. Pyruvate dehydrogenase D. Decarboxylation
Column II: i. α-Ketoglutaric acid ii. hydrogen acceptor iii. cytochrome C iv. acetyl Co A

The Intuition: Why Burn a Carbon Away?

Imagine you have a three-carbon molecule — pyruvate — that needs to enter the Krebs cycle. But the Krebs cycle is designed to work with two-carbon units (acetyl groups). So before pyruvate can enter, one of its three carbons must be removed. That removal is not just a snip; it's an oxidation (the molecule loses electrons) and a decarboxylation (it loses CO₂). The two happen together, hence the name.

Think of it like this: you have a three-legged stool that needs to become a two-legged one. You don't just saw off a leg — you also need to clean up the stump so it fits the next step. The "cleaning up" is the oxidation, and the "sawing off" is the release of CO₂.

The Precise Statement

Oxidative decarboxylation of pyruvate is the irreversible, enzyme-catalysed conversion of pyruvate (3C) into acetyl-CoA (2C) in the mitochondrial matrix. It is called oxidative because it involves the reduction of NAD⁺ to NADH (i.e., pyruvate loses electrons), and decarboxylation because one carbon atom is released as CO₂.

The overall reaction is:

This is catalysed by the pyruvate dehydrogenase complex (PDC) — a massive multi-enzyme machine that coordinates three enzymes and five cofactors.

What Actually Happens (Step by Step)

The pyruvate dehydrogenase complex does three things in sequence:

1. Decarboxylation — Pyruvate loses its carboxyl group (the -COO⁻ end) as CO₂. The remaining two-carbon fragment is attached to the cofactor thiamine pyrophosphate (TPP).

2. Oxidation — The two-carbon unit is transferred to lipoic acid (a cofactor), and in the process it is oxidised. The electrons lost by the carbon fragment are used to reduce lipoic acid's disulfide bond to two thiol groups.

3. Transfer to CoA — The oxidised two-carbon unit (now an acetyl group) is transferred to coenzyme A (CoA-SH), forming acetyl-CoA. Meanwhile, the reduced lipoic acid is re-oxidised by FAD, and FADH₂ then reduces NAD⁺ to NADH.

Why This Matters for Exams

• Location: Mitochondrial matrix (not cytoplasm — pyruvate must be transported in first).
• Products: 1 acetyl-CoA, 1 NADH, 1 CO₂ per pyruvate.
• Per glucose: Since one glucose yields two pyruvates, this step produces 2 acetyl-CoA, 2 NADH, and 2 CO₂.
• Irreversibility: This is a key regulatory point. The PDC is inhibited by high ATP, NADH, and acetyl-CoA (feedback inhibition) and activated by high ADP and NAD⁺. …