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NCERT Exemplar · Q45

Q.Complete the following reaction: phenol (C6H5OH) is treated with an aryldiazonium chloride, Ar–N2+ Cl−, in the presence of hydroxide ion (OH−, mildly alkaline medium). Give the product.

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An aryldiazonium salt couples with phenol in mild alkali by electrophilic aromatic substitution at the position para to –OH, giving a p-hydroxyazobenzene (an orange azo dye).

Concept – Azo coupling

The diazonium cation Ar–N2+ is a weak electrophile. It reacts only with strongly activated rings such as phenols and aromatic amines. In mild alkali the phenol is converted to the phenoxide ion (–O−), which is even more activating, so coupling occurs readily.

Regiochemistry

The –OH (or –O−) group directs the incoming diazonium electrophile ortho/para; the para position is preferred (less steric hindrance). The nitrogen of the diazonium becomes the –N=N– (azo) link.

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