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NCERT Exemplar · Q49

Q.How will you carry out the following conversions?

(i) toluene → p-toluidine
(ii) p-toluidine diazonium chloride → p-toluic acid
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The key idea is to use the directing effects of substituents on the benzene ring. For (i), we nitrate toluene (which gives mainly p-nitrotoluene due to the methyl group’s ortho/para direction), then reduce the nitro group to an amine. For (ii), we replace the diazonium group with a carboxyl group via a Sandmeyer-type reaction using cuprous cyanide, followed by hydrolysis.

Let’s break down each conversion with the reasoning behind every step.

(i) Toluene → p-Toluidine

Concept: The methyl group is an activating ortho/para director.

When you do an electrophilic substitution on toluene, the methyl group pushes electron density into the ring, making the ortho and para positions more reactive than the meta position. The para product is usually the major one because it’s less sterically hindered than the ortho product (which also forms but in smaller amount). So, to get p-toluidine, we first introduce a nitro group at the para position, then reduce it.

  1. Nitration of toluene Treat toluene with a mixture of concentrated nitric acid and concentrated sulfuric acid (nitrating mixture). The nitronium ion (NO2+\text{NO}_2^+) attacks the para position preferentially.

C6H5CH3+HNO3→H2SO4p-O2N-C6H4CH3+H2O\text{C}_6\text{H}_5\text{CH}_3 + \text{HNO}_3 \xrightarrow{\text{H}_2\text{SO}_4} p\text{-O}_2\text{N-C}_6\text{H}_4\text{CH}_3 + \text{H}_2\text{O}

The product is p-nitrotoluene (along with some o-nitrotoluene, which can be separated by distillation or crystallization).

  1. Reduction of the nitro group Reduce the nitro group to an amino group. A common laboratory method is catalytic hydrogenation (using H2\text{H}_2 gas with a palladium or nickel catalyst) or chemical reduction using tin and hydrochloric acid (Sn/HCl).

p-O2N-C6H4CH3+3H2→Pd/Cp-H2N-C6H4CH3+2H2Op\text{-O}_2\text{N-C}_6\text{H}_4\text{CH}_3 + 3\text{H}_2 \xrightarrow{\text{Pd/C}} p\text{-H}_2\text{N-C}_6\text{H}_4\text{CH}_3 + 2\text{H}_2\text{O}

The product is p-toluidine.

Watch out

A common mistake is to try direct amination of toluene. That doesn’t work because ammonia is not an electrophile for aromatic substitution. You must go through the nitro intermediate.

(ii) p-Toluidine Diazonium Chloride → p-Toluic Acid

Concept: The diazonium group is a superb leaving group that can be replaced by many nucleophiles.

Here, we want to replace the -N2+\text{-N}_2^+ group with a carboxyl group (-COOH\text{-COOH}). The standard route is to first replace the diazonium group with a cyano group (-CN\text{-CN}) via a Sandmeyer reaction, then hydrolyze the nitrile to a carboxylic acid.

  1. Formation of diazonium chloride Treat p-toluidine with sodium nitrite (NaNO2\text{NaNO}_2) and excess hydrochloric acid at 0–5°C. This gives the diazonium salt. p-H2N-C6H4CH3+NaNO2+2HCl→0−5∘Cp-CH3-C6H4-N2+Cl−+NaCl+2H2Op\text{-H}_2\text{N-C}_6\text{H}_4\text{CH}_3 + \text{NaNO}_2 + 2\text{HCl} \xrightarrow{0-5^\circ\text{C}} p\text{-CH}_3\text{-C}_6\text{H}_4\text{-N}_2^+\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O} …

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