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Physics · Ch 2 — Kinematics

Addition of Vectors

2.3.3

Addition of Vectors

Because vectors carry direction, A⃗+B⃗\vec A + \vec B cannot be found by ordinary addition of the numbers AA and BB — it needs a genuinely geometric (or, equivalently, component-wise) rule. The triangle law of addition gives that rule for two vectors inclined to each other at some angle:

Draw A⃗\vec A and B⃗\vec B as two sides of a triangle, taken in the same order — i.e. draw A⃗\vec A first, then draw B⃗\vec B starting from the head (tip) of A⃗\vec A. The resultant R⃗=A⃗+B⃗\vec R = \vec A + \vec B is then the third side of the triangle, drawn from the tail of A⃗\vec A directly to the head of B⃗\vec B.

Magnitude of the resultant. Let θ\theta be the angle between A⃗\vec A and B⃗\vec B. Extending the side representing A⃗\vec A and dropping a perpendicular from the head of B⃗\vec B onto that extension creates a right triangle from which AN=Bcos⁡θAN = B\cos\theta and BN=Bsin⁡θBN = B\sin\theta. Applying Pythagoras to this right triangle:

R2=(A+Bcos⁡θ)2+(Bsin⁡θ)2=A2+B2+2ABcos⁡θR^2 = (A + B\cos\theta)^2 + (B\sin\theta)^2 = A^2 + B^2 + 2AB\cos\theta

R=∣A⃗+B⃗∣=A2+B2+2ABcos⁡θ\boxed{R = |\vec A+\vec B| = \sqrt{A^2+B^2+2AB\cos\theta}}

Direction of the resultant. If R⃗\vec R makes angle α\alpha with A⃗\vec A, then from the same right triangle, …

Figure 2.16Head and tail of vectors

What this figure shows. Two vectors A⃗\vec A and B⃗\vec B each drawn as an arrow with its starting point labelled 'Tail' and its arrow tip labelled 'Head', the vocabulary used to state the triangle law. …

Figure 2.17Triangle law of addition

What this figure shows. Vector A⃗\vec A drawn from O to P, then vector B⃗\vec B drawn from P (the head of A⃗\vec A) to Q; the resultant R⃗=A⃗+B⃗\vec R = \vec A + \vec B is the third side of the triangle, drawn directly from O to Q. …

Figure 2.18Resultant vector and its direction by the triangle law

What this figure shows. The same O-P-Q triangle extended by dropping a perpendicular from Q onto the line OA extended (point N), forming right triangle OQN, used to read off Rcos⁡αR\cos\alpha and Rsin⁡αR\sin\alpha in terms of AA, BB and the angle θ\theta between them. …