Skip to content

Physics · Ch 2 — Kinematics

The Vector Product of Two Vectors

2.5.2

The Vector Product of Two Vectors

The vector product (or cross product) of two vectors combines them to produce a third vector, not a number — hence the name. Its magnitude equals the product of the two magnitudes and the sine of the angle between them, and its direction is perpendicular to the plane containing both original vectors:

A⃗×B⃗=C⃗=(ABsin⁡θ) n^\vec A \times \vec B = \vec C = (AB\sin\theta)\,\hat n

The direction n^\hat n is fixed by the right-hand (screw) rule: curl the fingers of the right hand from A⃗\vec A (first vector) towards B⃗\vec B (second vector) through the smaller angle between them; the thumb then points along n^\hat n, the direction of A⃗×B⃗\vec A\times\vec B.

Properties:

  1. A⃗×B⃗\vec A\times\vec B is always perpendicular to both A⃗\vec A and B⃗\vec B (i.e. orthogonal to the plane containing them), whether or not A⃗\vec A and B⃗\vec B are themselves perpendicular to each other.
  2. It is not commutative: A⃗×B⃗≠B⃗×A⃗\vec A\times\vec B \ne \vec B\times\vec A; in fact A⃗×B⃗=−(B⃗×A⃗)\vec A\times\vec B = -(\vec B\times\vec A) — the two cross products have equal magnitude ABsin⁡θAB\sin\theta but point in opposite directions.
  3. Maximum magnitude when sin⁡θ=1\sin\theta=1, i.e. θ=90°\theta=90° (perpendicular vectors): ∣A⃗×B⃗∣max=AB|\vec A\times\vec B|_{max}=AB.
  4. Minimum (zero) when sin⁡θ=0\sin\theta=0, i.e. θ=0°\theta=0° or 180°180° — the cross product of two parallel or anti-parallel (non-zero) vectors vanishes.
  5. Self-cross-product is always zero: A⃗×A⃗=(AAsin⁡0°)n^=0⃗\vec A\times\vec A = (AA\sin0°)\hat n = \vec 0; in physics the zero vector is simply written 00.
  6. Consequently i^×i^=j^×j^=k^×k^=0\hat i\times\hat i=\hat j\times\hat j=\hat k\times\hat k=0.
  7. For the orthogonal unit vectors, following the right-hand screw rule: i^×j^=k^\hat i\times\hat j=\hat k, j^×k^=i^\hat j\times\hat k=\hat i, k^×i^=j^\hat k\times\hat i=\hat j; and, since the product is anti-commutative, j^×i^=−k^\hat j\times\hat i=-\hat k, k^×j^=−i^\hat k\times\hat j=-\hat i, i^×k^=−j^\hat i\times\hat k=-\hat j.
  8. In component form, using the determinant recipe,

A⃗×B⃗=∣i^j^k^AxAyAzBxByBz∣=(AyBz−AzBy)i^+(AzBx−AxBz)j^+(AxBy−AyBx)k^\vec A\times\vec B = \begin{vmatrix}\hat i & \hat j & \hat k\\ A_x & A_y & A_z\\ B_x & B_y & B_z\end{vmatrix} = (A_yB_z-A_zB_y)\hat i + (A_zB_x-A_xB_z)\hat j + (A_xB_y-A_yB_x)\hat k

(note the middle, j^\hat j, component has its two terms in the opposite order to the i^\hat i and k^\hat k components — a common slip).

9. Area of a parallelogram: if A⃗\vec A and B⃗\vec B form two adjacent sides of a parallelogram, the parallelogram's area equals ∣A⃗×B⃗∣|\vec A\times\vec B|. …

Figure 2.22Vector product of two vectors

What this figure shows. Vectors A⃗\vec A and B⃗\vec B with their cross product C⃗=A⃗×B⃗\vec C = \vec A \times \vec B drawn perpendicular to the plane containing both, found by the right-hand screw rule; alongside it, B⃗×A⃗=−C⃗\vec B \times \vec A = -\vec C is drawn pointing the opposite way, showing the product is not com …

Figure 2.23Area of a parallelogram

What this figure shows. Vectors A⃗\vec A and B⃗\vec B drawn as adjacent sides of a parallelogram with included angle θ\theta; the parallelogram's area equals ∣A⃗×B⃗∣=ABsin⁡θ|\vec A \times \vec B| = AB\sin\theta, the magnitude of their cross produc …

Figure 2.24Area of a triangle

What this figure shows. The same parallelogram of vectors A⃗\vec A and B⃗\vec B split along its diagonal into two equal triangles, showing that a triangle with sides A⃗\vec A and B⃗\vec B has area $\tfrac{1}{2}|\vec A \times \ve …