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Choose the Best Answer · Q18

Q.A conductivity cell has been calibrated with a 0.01M, 1:1 electrolytic solution (specific conductance κ=1.25×10−3 S cm−1\kappa = 1.25\times10^{-3}\ \text{S cm}^{-1}) in the cell, and the measured resistance was 800 Ω\Omega at 25°C. The cell constant is

(a) 10−1 cm−110^{-1}\ \text{cm}^{-1}
(b) 101 cm−110^{1}\ \text{cm}^{-1}
(c) 1 cm−11\ \text{cm}^{-1}
(d) 5.7×10−125.7\times10^{-12}
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Step 1. The cell constant is defined as l/Al/A, and since κ=1R⋅lA\kappa = \dfrac{1}{R}\cdot\dfrac{l}{A}, rearranging gives cell constant =κ×R= \kappa \times R. …

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