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Write Brief Answer · Q14

Q.Can Fe3+\text{Fe}^{3+} oxidise bromide to bromine under standard conditions? Given: EFe3+/Fe2+o=0.771E^{o}_{\text{Fe}^{3+}/\text{Fe}^{2+}} = 0.771 V, EBr2/Br−o=1.09E^{o}_{\text{Br}_2/\text{Br}^{-}} = 1.09 V.

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Step 1. For Fe3+\text{Fe}^{3+} to oxidise Br−\text{Br}^- to Br2\text{Br}_2, the reaction 2Fe3++2Br−→2Fe2++Br22\text{Fe}^{3+}+2\text{Br}^- \rightarrow 2\text{Fe}^{2+}+\text{Br}_2 would need to be spontaneous, i.e. its EcelloE^{o}_{cell} must be positive.

Step 2. Here Fe3+/Fe2+\text{Fe}^{3+}/\text{Fe}^{2+} acts as the reduction (cathode) with Eo=0.771E^{o}=0.771 V, and Br−/Br2\text{Br}^-/\text{Br}_2 acts as the oxidation (anode), so Eoxo(Br−)=−1.09E^{o}_{ox}(\text{Br}^-) = -1.09 V.

Step 3. Ecello=Eredo(Fe3+/Fe2+)+Eoxo(Br−/Br2)=0.771+(−1.09)=−0.319E^{o}_{cell} = E^{o}_{red}(\text{Fe}^{3+}/\text{Fe}^{2+}) + E^{o}_{ox}(\text{Br}^-/\text{Br}_2) = 0.771 + (-1.09) = -0.319 V. …

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