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Choose the Best Answer · Q12

Q.While charging a lead storage battery,

(a) PbSO4\text{PbSO}_4 on cathode is reduced to Pb
(b) PbSO4\text{PbSO}_4 on anode is oxidised to PbO2\text{PbO}_2
(c) PbSO4\text{PbSO}_4 on anode is reduced to Pb
(d) PbSO4\text{PbSO}_4 on cathode is oxidised to Pb
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Step 1. During discharge of a lead storage battery, Pb (anode) is oxidised and PbO₂ (cathode) is reduced, and both produce PbSO₄ precipitate at their respective electrodes.

Step 2. Charging drives the reverse reaction, and in doing so swaps the roles of the two electrodes: the electrode that acted as the CATHODE during discharge now acts as the ANODE during charging, where the deposited PbSO₄ is OXIDISED back to PbO₂: PbSO4(s)+2H2O(l)→PbO2(s)+4H+(aq)+SO42−(aq)+2e−\text{PbSO}_4\text{(s)}+2\text{H}_2\text{O(l)} \rightarrow \text{PbO}_2\text{(s)}+4\text{H}^+\text{(aq)}+\text{SO}_4^{2-}\text{(aq)}+2e^-. …

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