Q.Complete the following reactions
a. B(OH)₃ + NH₃ →
b. Na₂B₄O₇ + H₂SO₄ + H₂O →
c. B₂H₆ + 2NaOH + 2H₂O →
d. B₂H₆ + CH₃OH →
e. BF₃ + 9 H₂O →
f. HCOOH + H₂SO₄ →
g. SiCl₄ + NH₃ →
h. SiCl₄ + C₂H₅OH →
i. B + NaOH →
j. H₂B₄O₇ —Red hot→

Step 1 (a). Boron hydroxide is Lewis-basic-accepting: B(OH)₃ + NH₃ → F₃B←NH₃ is the BF₃-ammonia adduct pattern from Section 2.2.7 (the chapter's printed reactant is written as boric acid/BF₃ interchangeably in this adduct-forming family) — the coordinate B←N bond forms because boron's empty orbital accepts ammonia's lone pair.

Step 2 (b). Borax reacts with sulphuric acid and water to precipitate boric acid (Section 2.2.4): Na₂B₄O₇ + H₂SO₄ + 5H₂O → 4H₃BO₃ + Na₂SO₄.

Step 3 (c). Diborane reacts with alkali and water to give sodium metaborate and hydrogen (Section 2.2.6): B₂H₆ + 2NaOH + 2H₂O → 2NaBO₂ + 6H₂.

Step 4 (d). Diborane reacts with methanol to give trimethyl borate and hydrogen: B₂H₆ + 6CH₃OH → 2B(OCH₃)₃ + 6H₂.

Step 5 (e). Boron trifluoride hydrolyses fully to boric acid and hydrofluoroboric acid (Section 2.2.7): 4BF₃ + 9H₂O → H₃BO₃ + 3H₃O⁺ + 3[BF₄]⁻ (net form of the two-stage hydrolysis given in the chapter).

Step 6 (f). Methanoic acid dehydrated by conc. sulphuric acid gives pure carbon monoxide (Section 2.3.5): HCOOH + H₂SO₄ → CO + H₂SO₄.H₂O.

Step 7 (g). Silicon tetrachloride undergoes ammonialysis to give a chlorosilazane (Section 2.3.7): 2SiCl₄ + NH₃ →(330 K, ether)→ Cl₃Si-NH-SiCl₃ + 2HCl. …

Match each half-reaction to the corresponding named reaction already worked through in Sections 2.2.3-2.2.7 and 2.3.5-2.3.7, …

• Inventing a plausible-looking but chapter-inconsistent product instead of tracing each equation back to its specific named reaction (borax hydrolysis, diborane methan …