Choose the Best Answer · Q8
Q.Oxidation state of carbon in its hydrides
a) +4
b) -4
c) +3
d) +2
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Start your 14-day free trial to unlock the full solution →Step 1. Table 2.1 lists the p-block group oxidation states, and for group 14 (carbon's group) the 'other observed oxidation states' entry is +2, -4.
Step 2. In a carbon hydride such as methane, CH₄, each hydrogen is assigned its usual oxidation state of +1 (hydrogen bonded to a less electronegative or comparably electronegative element still takes +1 by convention here since carbon is more electronegative than hydrogen).
Step 3. For the neutral molecule CH₄, the oxidation states must sum to zero: x + 4(+1) = 0, so x = -4. …
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